Progressive Care RN — Lead Patient Care & Growth

Bon Secours Mercy Health; Youngstown (OH); On-site; USD 65,000 - 90,000; Full time

Benefits offered by this job

Competitive pay

Incentives

403(b) with employer contributions

Health, dental, vision coverage

Paid time off

Job summary

Bon Secours Mercy Health is hiring a Registered Nurse for the Progressive Care (Step down) unit at St. Elizabeth Youngstown Hospital. The role focuses on delivering high-quality nursing care through careful assessment, planning, and collaboration with the care team.

The RN will coordinate care across departments, ensure medication safety, and participate in ongoing quality improvement to enhance patient outcomes. BSN preferred, RN licensure required, and certifications as applicable.

Qualifications

• Bachelor of Science in Nursing (BSN) preferred.
• Current state licensure as a Registered Nurse (RN).
• BLS or ACLS preferred at hire; ACLS required within 6 months of hire.

Responsibilities

• Collaborate with the interdisciplinary care team to plan and deliver care.
• Perform initial and ongoing patient assessment and develop plans of care.
• Coordinate patient care across Med-Surg and ICU units.
• Administer medications safely following policies.
• Participate in quality improvement and patient safety initiatives.

Skills

Nursing assessment

Care coordination

Patient safety

Medication administration

Interdisciplinary collaboration

Education

BSN preferred

RN licensure

BLS/ACLS

Job description

Bon Secours Mercy Health is hiring a Registered Nurse for the Progressive Care (Step down) unit at St. Elizabeth Youngstown Hospital. The role focuses on delivering high-quality nursing care through careful assessment, planning, and collaboration with the care team.

The RN will coordinate care across departments, ensure medication safety, and participate in ongoing quality improvement to enhance patient outcomes. BSN preferred, RN licensure required, and certifications as applicable.