Tech-Driven Retail Sales Consultant — Uncapped Earnings

Victra - Verizon Authorized Retailer; Austin (MN); On-site; USD 40,000 - 64,000; Full time

Benefits offered by this job

Health insurance

Dental insurance

Vision insurance

401K Match

Tuition Reimbursement

Paid Training

Paid time off

Referral Bonus

Career Advancement

Job summary

Victra is Verizon's largest premium retailer in the United States. As a full-time Retail Sales Consultant, you will deliver world-class service to Every Guest and connect guests to technology that matters, creating the ultimate in-store experience.

You will meet sales goals, work with peers and leaders, and participate in training. The role includes benefits like health, dental, vision, 401K, tuition reimbursement, and opportunities for advancement, with paid training and a ramp-up period.

Qualifications

• High school diploma or GED.
• 1+ year of customer service, preferably in retail or sales.
• Legally authorized to work in the United States.
• Willingness to work evenings, weekends, holidays, and peak periods.

Responsibilities

• Achieve and exceed monthly sales goals.
• Work alongside peers and store leaders, sharing ideas while serving customers.
• Provide product benefits and solution recommendations through exceptional service.
• Create personal connections with guests to make tech look simple.
• Assist with merchandising and operational functions.

Skills

Customer service

Retail sales

Communication

Work schedule flexibility

Education

High school diploma or GED

Job description

Victra is Verizon's largest premium retailer in the United States. As a full-time Retail Sales Consultant, you will deliver world-class service to Every Guest and connect guests to technology that matters, creating the ultimate in-store experience.

You will meet sales goals, work with peers and leaders, and participate in training. The role includes benefits like health, dental, vision, 401K, tuition reimbursement, and opportunities for advancement, with paid training and a ramp-up period.